The prices of 23” TV sets sampled by a consumer guide were as follows: $400, $600, $550, $450, $700, $500, and $650. Build a 98 percent confidence interval for the mean.

Question 1

Design a 95 percent confidence interval for the proportion of defectives in a large lot, if a sample of 200 showed 12 defectives.
Question 2

The prices of 23” TV sets sampled by a consumer guide were as follows: $400, $600, $550, $450, $700, $500, and $650. Build a 98 percent confidence interval for [...]

You need to decide whether you should invest in a particular stock. You would like to invest if the price is likely to rise in the long run. You have data on the daily average price of this stock over the past 12 months. Your best action is to:

1 of 25
Excel was used to obtain the following quadratic trend equation:
Sales = 100 – 10X + 15X2
The data used was from 1989 through 1998, coded 0 to 9. The forecast for 1999 is __________.
1,225
980
1,500
1,600

2 of 25
Which of the following is used to determine observations that have an influential effect on the fitted [...]

The prices of 23” TV sets sampled by a consumer guide were as follows: $400, $600, $550, $450, $700, $500, and $650. Build a 98 percent confidence interval for the mean.

Question 1
 
Design a 95 percent confidence interval for the proportion of defectives in a large lot, if a sample of 200 showed 12 defectives.
 
 
 
 
Question 2
 
The prices of 23” TV sets sampled by a consumer guide were as follows: $400, $600, $550, $450, $700, $500, and $650. Build a 98 percent confidence interval for the mean.
 
 
 
 
Question [...]

Design a 95 percent confidence interval for the proportion of defectives in a large lot, if a sample of 200 showed 12 defectives.

Question 1
 
Design a 95 percent confidence interval for the proportion of defectives in a large lot, if a sample of 200 showed 12 defectives.
 
 
 
 
Question 2
 
The prices of 23” TV sets sampled by a consumer guide were as follows: $400, $600, $550, $450, $700, $500, and $650. Build a 98 percent confidence interval for the mean.
 
 
 
 
Question [...]